Base | Representation |
---|---|
bin | 100101001011011100011101… |
… | …111100000110101101110111 |
3 | 210102221210201220011122011201 |
4 | 211023130131330012231313 |
5 | 132413004041232041211 |
6 | 1335433215410513331 |
7 | 46304340235252015 |
oct | 4513343574065567 |
9 | 712853656148151 |
10 | 163514202221431 |
11 | 48111a90390636 |
12 | 1640a193595847 |
13 | 7031427b353c9 |
14 | 2c541b593b8b5 |
15 | 13d85a64750c1 |
hex | 94b71df06b77 |
163514202221431 has 2 divisors, whose sum is σ = 163514202221432. Its totient is φ = 163514202221430.
The previous prime is 163514202221393. The next prime is 163514202221443. The reversal of 163514202221431 is 134122202415361.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 163514202221431 - 211 = 163514202219383 is a prime.
It is a super-2 number, since 2×1635142022214312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (163514209221431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81757101110715 + 81757101110716.
It is an arithmetic number, because the mean of its divisors is an integer number (81757101110716).
Almost surely, 2163514202221431 is an apocalyptic number.
163514202221431 is a deficient number, since it is larger than the sum of its proper divisors (1).
163514202221431 is an equidigital number, since it uses as much as digits as its factorization.
163514202221431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 37.
Adding to 163514202221431 its reverse (134122202415361), we get a palindrome (297636404636792).
The spelling of 163514202221431 in words is "one hundred sixty-three trillion, five hundred fourteen billion, two hundred two million, two hundred twenty-one thousand, four hundred thirty-one".
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