163614210140021 has 4 divisors (see below), whose sum is σ = 163614582244044. Its totient is φ = 163613838036000.

The previous prime is 163614210140011. The next prime is 163614210140053. The reversal of 163614210140021 is 120041012416361.

163614210140021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 111835679907121 + 51778530232900 = 10575239^2 + 7195730^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-163614210140021 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 163614210140021.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (163614210140011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185391680 + ... + 186272121.

It is an arithmetic number, because the mean of its divisors is an integer number (40903645561011).

Almost surely, 2^{163614210140021} is an apocalyptic number.

It is an amenable number.

163614210140021 is a deficient number, since it is larger than the sum of its proper divisors (372104023).

163614210140021 is an equidigital number, since it uses as much as digits as its factorization.

163614210140021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 372104022.

The product of its (nonzero) digits is 6912, while the sum is 32.

Adding to 163614210140021 its reverse (120041012416361), we get a palindrome (283655222556382).

The spelling of 163614210140021 in words is "one hundred sixty-three trillion, six hundred fourteen billion, two hundred ten million, one hundred forty thousand, twenty-one".