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163642122115 = 532728424423
BaseRepresentation
bin1001100001100111010…
…1001001111110000011
3120122101111112010021121
42120121311021332003
510140114340401430
6203102014333111
714552130042013
oct2303165117603
9518344463247
10163642122115
116344479143a
122786b4ba197
131257b9a7474
147cc5509c43
1543cb5bea7a
hex2619d49f83

163642122115 has 4 divisors (see below), whose sum is σ = 196370546544. Its totient is φ = 130913697688.

The previous prime is 163642122047. The next prime is 163642122151. The reversal of 163642122115 is 511221246361.

163642122115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 163642122115 - 217 = 163641991043 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16364212207 + ... + 16364212216.

It is an arithmetic number, because the mean of its divisors is an integer number (49092636636).

Almost surely, 2163642122115 is an apocalyptic number.

163642122115 is a deficient number, since it is larger than the sum of its proper divisors (32728424429).

163642122115 is an equidigital number, since it uses as much as digits as its factorization.

163642122115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32728424428.

The product of its digits is 17280, while the sum is 34.

Adding to 163642122115 its reverse (511221246361), we get a palindrome (674863368476).

The spelling of 163642122115 in words is "one hundred sixty-three billion, six hundred forty-two million, one hundred twenty-two thousand, one hundred fifteen".

Divisors: 1 5 32728424423 163642122115