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1639394025701 is a prime number
BaseRepresentation
bin10111110110110011011…
…111111010000011100101
312210201120012002100000012
4113312303133322003211
5203324434332310301
63253043251300005
7226304466203645
oct27666337720345
95721505070005
101639394025701
11582299209023
122258858aa605
13bb79559a613
14594c05d8525
152c99ecbcebb
hex17db37fa0e5

1639394025701 has 2 divisors, whose sum is σ = 1639394025702. Its totient is φ = 1639394025700.

The previous prime is 1639394025637. The next prime is 1639394025733. The reversal of 1639394025701 is 1075204939361.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1187206368100 + 452187657601 = 1089590^2 + 672449^2 .

It is a cyclic number.

It is not a de Polignac number, because 1639394025701 - 26 = 1639394025637 is a prime.

It is a super-2 number, since 2×16393940257012 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1639394025701.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1639394025761) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 819697012850 + 819697012851.

It is an arithmetic number, because the mean of its divisors is an integer number (819697012851).

Almost surely, 21639394025701 is an apocalyptic number.

It is an amenable number.

1639394025701 is a deficient number, since it is larger than the sum of its proper divisors (1).

1639394025701 is an equidigital number, since it uses as much as digits as its factorization.

1639394025701 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1224720, while the sum is 50.

The spelling of 1639394025701 in words is "one trillion, six hundred thirty-nine billion, three hundred ninety-four million, twenty-five thousand, seven hundred one".