Base | Representation |
---|---|
bin | 10111110111010111111… |
… | …110110111110000100101 |
3 | 12210210010211212002000020 |
4 | 113313113332313300211 |
5 | 203332213031410113 |
6 | 3253224114505353 |
7 | 226325611014552 |
oct | 27672776676045 |
9 | 5723124762006 |
10 | 1640006122533 |
11 | 582582779479 |
12 | 225a16895259 |
13 | bb8623402ac |
14 | 5953ba0da29 |
15 | 2c9d88ca023 |
hex | 17dd7fb7c25 |
1640006122533 has 4 divisors (see below), whose sum is σ = 2186674830048. Its totient is φ = 1093337415020.
The previous prime is 1640006122463. The next prime is 1640006122537. The reversal of 1640006122533 is 3352216000461.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1640006122533 - 233 = 1631416187941 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1640006122494 and 1640006122503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1640006122537) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 273334353753 + ... + 273334353758.
It is an arithmetic number, because the mean of its divisors is an integer number (546668707512).
Almost surely, 21640006122533 is an apocalyptic number.
It is an amenable number.
1640006122533 is a deficient number, since it is larger than the sum of its proper divisors (546668707515).
1640006122533 is an equidigital number, since it uses as much as digits as its factorization.
1640006122533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 546668707514.
The product of its (nonzero) digits is 25920, while the sum is 33.
The spelling of 1640006122533 in words is "one trillion, six hundred forty billion, six million, one hundred twenty-two thousand, five hundred thirty-three".
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