Base | Representation |
---|---|
bin | 1110111010110100011110… |
… | …0001011001101111111101 |
3 | 2011002011202122222200021120 |
4 | 3232231013201121233331 |
5 | 4122224214042320411 |
6 | 54515425132221153 |
7 | 3312061324531041 |
oct | 356550741315775 |
9 | 64064678880246 |
10 | 16403680041981 |
11 | 5254841816881 |
12 | 1a0b18730a7b9 |
13 | 91cb2537cc8b |
14 | 409d29b48021 |
15 | 1d6a6d8e7106 |
hex | eeb47859bfd |
16403680041981 has 4 divisors (see below), whose sum is σ = 21871573389312. Its totient is φ = 10935786694652.
The previous prime is 16403680041943. The next prime is 16403680042109. The reversal of 16403680041981 is 18914008630461.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 16403680041981 - 217 = 16403679910909 is a prime.
It is a super-2 number, since 2×164036800419812 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16403680041181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2733946673661 + ... + 2733946673666.
It is an arithmetic number, because the mean of its divisors is an integer number (5467893347328).
Almost surely, 216403680041981 is an apocalyptic number.
It is an amenable number.
16403680041981 is a deficient number, since it is larger than the sum of its proper divisors (5467893347331).
16403680041981 is an equidigital number, since it uses as much as digits as its factorization.
16403680041981 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5467893347330.
The product of its (nonzero) digits is 995328, while the sum is 51.
The spelling of 16403680041981 in words is "sixteen trillion, four hundred three billion, six hundred eighty million, forty-one thousand, nine hundred eighty-one".
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