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16405398941 is a prime number
BaseRepresentation
bin11110100011101011…
…01000010110011101
31120100022122121121012
433101311220112131
5232044240231231
611311520345005
71120353406301
oct172165502635
946308577535
1016405398941
116a59469048
12321a175165
131715a68069
14b18b3dd01
156603c3e2b
hex3d1d6859d

16405398941 has 2 divisors, whose sum is σ = 16405398942. Its totient is φ = 16405398940.

The previous prime is 16405398907. The next prime is 16405398953. The reversal of 16405398941 is 14989350461.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9217920100 + 7187478841 = 96010^2 + 84779^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16405398941 is a prime.

It is a super-2 number, since 2×164053989412 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 16405398941.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16405397941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8202699470 + 8202699471.

It is an arithmetic number, because the mean of its divisors is an integer number (8202699471).

Almost surely, 216405398941 is an apocalyptic number.

It is an amenable number.

16405398941 is a deficient number, since it is larger than the sum of its proper divisors (1).

16405398941 is an equidigital number, since it uses as much as digits as its factorization.

16405398941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 933120, while the sum is 50.

The spelling of 16405398941 in words is "sixteen billion, four hundred five million, three hundred ninety-eight thousand, nine hundred forty-one".