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1640880493309 is a prime number
BaseRepresentation
bin10111111000001100000…
…110010101001011111101
312210212101210010201020001
4113320030012111023331
5203341010401241214
63253450551354301
7226356356030521
oct27701406251375
95725353121201
101640880493309
11582991296152
1222601b682991
13bb971532255
14595c1bb7d81
152ca3a542c74
hex17e0c1952fd

1640880493309 has 2 divisors, whose sum is σ = 1640880493310. Its totient is φ = 1640880493308.

The previous prime is 1640880493249. The next prime is 1640880493363. The reversal of 1640880493309 is 9033940880461.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1487721757284 + 153158736025 = 1219722^2 + 391355^2 .

It is a cyclic number.

It is not a de Polignac number, because 1640880493309 - 237 = 1503441539837 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1640880493309.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1640880497309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 820440246654 + 820440246655.

It is an arithmetic number, because the mean of its divisors is an integer number (820440246655).

Almost surely, 21640880493309 is an apocalyptic number.

It is an amenable number.

1640880493309 is a deficient number, since it is larger than the sum of its proper divisors (1).

1640880493309 is an equidigital number, since it uses as much as digits as its factorization.

1640880493309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4478976, while the sum is 55.

The spelling of 1640880493309 in words is "one trillion, six hundred forty billion, eight hundred eighty million, four hundred ninety-three thousand, three hundred nine".