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164215863980 = 22571172970457
BaseRepresentation
bin1001100011110000000…
…1110011101010101100
3120200212111010020011022
42120330001303222230
510142303230121410
6203234551513312
714602264545560
oct2307401635254
9520774106138
10164215863980
1163709635173
12279ab688838
131264080b2ac
147d3b7b96a0
154411b52455
hex263c073aac

164215863980 has 24 divisors (see below), whose sum is σ = 394118073888. Its totient is φ = 56302581888.

The previous prime is 164215863967. The next prime is 164215863997. The reversal of 164215863980 is 89368512461.

It is a super-3 number, since 3×1642158639803 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 586485089 + ... + 586485368.

It is an arithmetic number, because the mean of its divisors is an integer number (16421586412).

Almost surely, 2164215863980 is an apocalyptic number.

164215863980 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

164215863980 is an abundant number, since it is smaller than the sum of its proper divisors (229902209908).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

164215863980 is a wasteful number, since it uses less digits than its factorization.

164215863980 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1172970473 (or 1172970471 counting only the distinct ones).

The product of its (nonzero) digits is 2488320, while the sum is 53.

The spelling of 164215863980 in words is "one hundred sixty-four billion, two hundred fifteen million, eight hundred sixty-three thousand, nine hundred eighty".

Divisors: 1 2 4 5 7 10 14 20 28 35 70 140 1172970457 2345940914 4691881828 5864852285 8210793199 11729704570 16421586398 23459409140 32843172796 41053965995 82107931990 164215863980