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16423102242689 is a prime number
BaseRepresentation
bin1110111011111100110100…
…1011001101111110000001
32011011000220020021200220112
43232333031023031332001
54123034003133231224
654532400301321105
73313346532521642
oct356771513157601
964130806250815
1016423102242689
115261aa908071a
121a12aa7866195
139218cc13302c
1440ac4d3c56c9
151d7308a7d30e
hexeefcd2cdf81

16423102242689 has 2 divisors, whose sum is σ = 16423102242690. Its totient is φ = 16423102242688.

The previous prime is 16423102242683. The next prime is 16423102242691. The reversal of 16423102242689 is 98624220132461.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13216191326464 + 3206910916225 = 3635408^2 + 1790785^2 .

It is a cyclic number.

It is not a de Polignac number, because 16423102242689 - 236 = 16354382765953 is a prime.

It is a super-2 number, since 2×164231022426892 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 16423102242691, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (16423102242683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8211551121344 + 8211551121345.

It is an arithmetic number, because the mean of its divisors is an integer number (8211551121345).

Almost surely, 216423102242689 is an apocalyptic number.

It is an amenable number.

16423102242689 is a deficient number, since it is larger than the sum of its proper divisors (1).

16423102242689 is an equidigital number, since it uses as much as digits as its factorization.

16423102242689 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1990656, while the sum is 50.

The spelling of 16423102242689 in words is "sixteen trillion, four hundred twenty-three billion, one hundred two million, two hundred forty-two thousand, six hundred eighty-nine".