Base | Representation |
---|---|
bin | 11110100110111110… |
… | …10110000000000001 |
3 | 1120102020210112110021 |
4 | 33103133112000001 |
5 | 232123334023131 |
6 | 11314350333441 |
7 | 1121141065504 |
oct | 172337260001 |
9 | 46366715407 |
10 | 16433111041 |
11 | 6a73076606 |
12 | 32274ba281 |
13 | 171b71b859 |
14 | b1c6b513b |
15 | 662a49e11 |
hex | 3d37d6001 |
16433111041 has 2 divisors, whose sum is σ = 16433111042. Its totient is φ = 16433111040.
The previous prime is 16433111027. The next prime is 16433111111. The reversal of 16433111041 is 14011133461.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10301438016 + 6131673025 = 101496^2 + 78305^2 .
It is a cyclic number.
It is not a de Polignac number, because 16433111041 - 233 = 7843176449 is a prime.
It is a super-2 number, since 2×164331110412 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 16433110997 and 16433111015.
It is not a weakly prime, because it can be changed into another prime (16433111341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8216555520 + 8216555521.
It is an arithmetic number, because the mean of its divisors is an integer number (8216555521).
Almost surely, 216433111041 is an apocalyptic number.
It is an amenable number.
16433111041 is a deficient number, since it is larger than the sum of its proper divisors (1).
16433111041 is an equidigital number, since it uses as much as digits as its factorization.
16433111041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
The spelling of 16433111041 in words is "sixteen billion, four hundred thirty-three million, one hundred eleven thousand, forty-one".
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