Base | Representation |
---|---|
bin | 11110100110111110… |
… | …10110111110100011 |
3 | 1120102020210201221111 |
4 | 33103133112332203 |
5 | 232123334140133 |
6 | 11314350404151 |
7 | 1121141113252 |
oct | 172337267643 |
9 | 46366721844 |
10 | 16433115043 |
11 | 6a73079614 |
12 | 3227500657 |
13 | 171b720617 |
14 | b1c6b6799 |
15 | 662a4b1cd |
hex | 3d37d6fa3 |
16433115043 has 4 divisors (see below), whose sum is σ = 16494204960. Its totient is φ = 16372025128.
The previous prime is 16433115037. The next prime is 16433115047. The reversal of 16433115043 is 34051133461.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 16433115043 - 29 = 16433114531 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 16433114996 and 16433115014.
It is not an unprimeable number, because it can be changed into a prime (16433115047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30544555 + ... + 30545092.
It is an arithmetic number, because the mean of its divisors is an integer number (4123551240).
Almost surely, 216433115043 is an apocalyptic number.
16433115043 is a deficient number, since it is larger than the sum of its proper divisors (61089917).
16433115043 is an equidigital number, since it uses as much as digits as its factorization.
16433115043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61089916.
The product of its (nonzero) digits is 12960, while the sum is 31.
The spelling of 16433115043 in words is "sixteen billion, four hundred thirty-three million, one hundred fifteen thousand, forty-three".
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