Base | Representation |
---|---|
bin | 1110111100100011000001… |
… | …0001000000111110111101 |
3 | 2011012000100201222111220010 |
4 | 3233020300101000332331 |
5 | 4123221002242010331 |
6 | 54541213502013433 |
7 | 3314161563466011 |
oct | 357106021007675 |
9 | 64160321874803 |
10 | 16433354641341 |
11 | 526638a307560 |
12 | 1a14a89277279 |
13 | 9228741c2901 |
14 | 40b542c8a541 |
15 | 1d7708b95e46 |
hex | ef230440fbd |
16433354641341 has 16 divisors (see below), whose sum is σ = 24308197931520. Its totient is φ = 9790801942320.
The previous prime is 16433354641339. The next prime is 16433354641367. The reversal of 16433354641341 is 14314645333461.
16433354641341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 16433354641341 - 21 = 16433354641339 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16433352641341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4220171305 + ... + 4220175198.
It is an arithmetic number, because the mean of its divisors is an integer number (1519262370720).
Almost surely, 216433354641341 is an apocalyptic number.
16433354641341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
16433354641341 is a deficient number, since it is larger than the sum of its proper divisors (7874843290179).
16433354641341 is a wasteful number, since it uses less digits than its factorization.
16433354641341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8440346576.
The product of its digits is 3732480, while the sum is 48.
The spelling of 16433354641341 in words is "sixteen trillion, four hundred thirty-three billion, three hundred fifty-four million, six hundred forty-one thousand, three hundred forty-one".
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