Base | Representation |
---|---|
bin | 1110111100100011010110… |
… | …0111111110000011100110 |
3 | 2011012000121000011002011201 |
4 | 3233020311213332003212 |
5 | 4123221143300412432 |
6 | 54541230432553114 |
7 | 3314164034610031 |
oct | 357106547760346 |
9 | 64160530132151 |
10 | 16433444544742 |
11 | 5266426032295 |
12 | 1a14ab33b279a |
13 | 922889a0c8a4 |
14 | 40b550bb0018 |
15 | 1d7711a03ee7 |
hex | ef2359fe0e6 |
16433444544742 has 4 divisors (see below), whose sum is σ = 24650166817116. Its totient is φ = 8216722272370.
The previous prime is 16433444544731. The next prime is 16433444544743. The reversal of 16433444544742 is 24744544433461.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×164334445447422 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16433444544743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4108361136184 + ... + 4108361136187.
It is an arithmetic number, because the mean of its divisors is an integer number (6162541704279).
Almost surely, 216433444544742 is an apocalyptic number.
16433444544742 is a deficient number, since it is larger than the sum of its proper divisors (8216722272374).
16433444544742 is an equidigital number, since it uses as much as digits as its factorization.
16433444544742 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8216722272373.
The product of its digits is 61931520, while the sum is 55.
The spelling of 16433444544742 in words is "sixteen trillion, four hundred thirty-three billion, four hundred forty-four million, five hundred forty-four thousand, seven hundred forty-two".
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