16440121433 has 2 divisors, whose sum is σ = 16440121434. Its totient is φ = 16440121432.

The previous prime is 16440121427. The next prime is 16440121457. The reversal of 16440121433 is 33412104461.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9721368409 + 6718753024 = 98597^2 + 81968^2 .

It is a cyclic number.

It is not a de Polignac number, because 16440121433 - 2¹⁴ = 16440105049 is a prime.

It is a super-3 number, since 3×16440121433³ (a number of 32 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 16440121396 and 16440121405.

It is not a weakly prime, because it can be changed into another prime (16440121403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8220060716 + 8220060717.

It is an arithmetic number, because the mean of its divisors is an integer number (8220060717).

Almost surely, 2^16440121433 is an apocalyptic number.

It is an amenable number.

16440121433 is a deficient number, since it is larger than the sum of its proper divisors (1).

16440121433 is an equidigital number, since it uses as much as digits as its factorization.

16440121433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 16440121433 its reverse (33412104461), we get a palindrome (49852225894).

The spelling of 16440121433 in words is "sixteen billion, four hundred forty million, one hundred twenty-one thousand, four hundred thirty-three".