Base | Representation |
---|---|
bin | 11110100111110101… |
… | …10111001111100011 |
3 | 1120102202101001021022 |
4 | 33103322313033203 |
5 | 232132210400331 |
6 | 11315205120055 |
7 | 1121256312641 |
oct | 172372671743 |
9 | 46382331238 |
10 | 16440325091 |
11 | 6a77153633 |
12 | 32299b902b |
13 | 1720076318 |
14 | b1d632191 |
15 | 6634c267b |
hex | 3d3eb73e3 |
16440325091 has 4 divisors (see below), whose sum is σ = 16446038400. Its totient is φ = 16434611784.
The previous prime is 16440325087. The next prime is 16440325093. The reversal of 16440325091 is 19052304461.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 16440325091 - 22 = 16440325087 is a prime.
It is a super-3 number, since 3×164403250913 (a number of 32 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16440325093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2852336 + ... + 2858093.
It is an arithmetic number, because the mean of its divisors is an integer number (4111509600).
Almost surely, 216440325091 is an apocalyptic number.
16440325091 is a deficient number, since it is larger than the sum of its proper divisors (5713309).
16440325091 is an equidigital number, since it uses as much as digits as its factorization.
16440325091 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5713308.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 16440325091 in words is "sixteen billion, four hundred forty million, three hundred twenty-five thousand, ninety-one".
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