Base | Representation |
---|---|
bin | 11110100111111000… |
… | …11101100100000001 |
3 | 1120102210011100011121 |
4 | 33103330131210001 |
5 | 232132312303233 |
6 | 11315222112241 |
7 | 1121263006546 |
oct | 172374354401 |
9 | 46383140147 |
10 | 16440744193 |
11 | 6a7740a4a5 |
12 | 3229b7b681 |
13 | 1720192003 |
14 | b1d700bcd |
15 | 66355692d |
hex | 3d3f1d901 |
16440744193 has 2 divisors, whose sum is σ = 16440744194. Its totient is φ = 16440744192.
The previous prime is 16440744191. The next prime is 16440744211. The reversal of 16440744193 is 39144704461.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10696316929 + 5744427264 = 103423^2 + 75792^2 .
It is a cyclic number.
It is not a de Polignac number, because 16440744193 - 21 = 16440744191 is a prime.
It is a super-3 number, since 3×164407441933 (a number of 32 digits) contains 333 as substring.
Together with 16440744191, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (16440744191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8220372096 + 8220372097.
It is an arithmetic number, because the mean of its divisors is an integer number (8220372097).
Almost surely, 216440744193 is an apocalyptic number.
It is an amenable number.
16440744193 is a deficient number, since it is larger than the sum of its proper divisors (1).
16440744193 is an equidigital number, since it uses as much as digits as its factorization.
16440744193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 290304, while the sum is 43.
The spelling of 16440744193 in words is "sixteen billion, four hundred forty million, seven hundred forty-four thousand, one hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •