Base | Representation |
---|---|
bin | 1110111100111111101011… |
… | …1000000101101011010111 |
3 | 2011012202012221222202201021 |
4 | 3233033322320011223113 |
5 | 4123332232001132421 |
6 | 54544525155342011 |
7 | 3314553342253435 |
oct | 357177270055327 |
9 | 64182187882637 |
10 | 16441048849111 |
11 | 5269678504757 |
12 | 1a16475bb1907 |
13 | 9234cc28a683 |
14 | 40ba72ab3d55 |
15 | 1d7a093db341 |
hex | ef3fae05ad7 |
16441048849111 has 2 divisors, whose sum is σ = 16441048849112. Its totient is φ = 16441048849110.
The previous prime is 16441048849079. The next prime is 16441048849117. The reversal of 16441048849111 is 11194884014461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16441048849111 - 25 = 16441048849079 is a prime.
It is a super-3 number, since 3×164410488491113 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16441048849117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8220524424555 + 8220524424556.
It is an arithmetic number, because the mean of its divisors is an integer number (8220524424556).
Almost surely, 216441048849111 is an apocalyptic number.
16441048849111 is a deficient number, since it is larger than the sum of its proper divisors (1).
16441048849111 is an equidigital number, since it uses as much as digits as its factorization.
16441048849111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 884736, while the sum is 52.
The spelling of 16441048849111 in words is "sixteen trillion, four hundred forty-one billion, forty-eight million, eight hundred forty-nine thousand, one hundred eleven".
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