Base | Representation |
---|---|
bin | 1110111101000001110100… |
… | …0010010100111101011011 |
3 | 2011012210200220101201222121 |
4 | 3233100131002110331123 |
5 | 4123334420210132431 |
6 | 54545102111202111 |
7 | 3314603501514322 |
oct | 357203502247533 |
9 | 64183626351877 |
10 | 16441621958491 |
11 | 5269941a66274 |
12 | 1a165b5b16337 |
13 | 923590c2c652 |
14 | 40bac8c5b0b9 |
15 | 1d7a3e896611 |
hex | ef41d094f5b |
16441621958491 has 2 divisors, whose sum is σ = 16441621958492. Its totient is φ = 16441621958490.
The previous prime is 16441621958441. The next prime is 16441621958611. The reversal of 16441621958491 is 19485912614461.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16441621958491 - 221 = 16441619861339 is a prime.
It is a super-3 number, since 3×164416219584913 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (16441621958441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8220810979245 + 8220810979246.
It is an arithmetic number, because the mean of its divisors is an integer number (8220810979246).
Almost surely, 216441621958491 is an apocalyptic number.
16441621958491 is a deficient number, since it is larger than the sum of its proper divisors (1).
16441621958491 is an equidigital number, since it uses as much as digits as its factorization.
16441621958491 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14929920, while the sum is 61.
The spelling of 16441621958491 in words is "sixteen trillion, four hundred forty-one billion, six hundred twenty-one million, nine hundred fifty-eight thousand, four hundred ninety-one".
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