Base | Representation |
---|---|
bin | 1110111101000011010010… |
… | …0001111001001011110111 |
3 | 2011012211201101001200020211 |
4 | 3233100310201321023313 |
5 | 4123341222110444203 |
6 | 54545205151210251 |
7 | 3314616325655131 |
oct | 357206441711367 |
9 | 64184641050224 |
10 | 16442016109303 |
11 | 526a0244a6644 |
12 | 1a166a5b16987 |
13 | 9236247a3795 |
14 | 40bb2533c051 |
15 | 1d7a642a1c6d |
hex | ef4348792f7 |
16442016109303 has 2 divisors, whose sum is σ = 16442016109304. Its totient is φ = 16442016109302.
The previous prime is 16442016109223. The next prime is 16442016109357. The reversal of 16442016109303 is 30390161024461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16442016109303 - 213 = 16442016101111 is a prime.
It is a super-3 number, since 3×164420161093033 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16442016109903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221008054651 + 8221008054652.
It is an arithmetic number, because the mean of its divisors is an integer number (8221008054652).
Almost surely, 216442016109303 is an apocalyptic number.
16442016109303 is a deficient number, since it is larger than the sum of its proper divisors (1).
16442016109303 is an equidigital number, since it uses as much as digits as its factorization.
16442016109303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 40.
The spelling of 16442016109303 in words is "sixteen trillion, four hundred forty-two billion, sixteen million, one hundred nine thousand, three hundred three".
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