164421214303 has 4 divisors (see below), whose sum is σ = 164422040328. Its totient is φ = 164420388280.

The previous prime is 164421214297. The next prime is 164421214333. The reversal of 164421214303 is 303412124461.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 164421214303 - 2¹³ = 164421206111 is a prime.

It is a super-3 number, since 3×164421214303³ (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (164421214333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88800 + ... + 580282.

It is an arithmetic number, because the mean of its divisors is an integer number (41105510082).

Almost surely, 2^164421214303 is an apocalyptic number.

164421214303 is a deficient number, since it is larger than the sum of its proper divisors (826025).

164421214303 is an equidigital number, since it uses as much as digits as its factorization.

164421214303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 826024.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 164421214303 its reverse (303412124461), we get a palindrome (467833338764).

The spelling of 164421214303 in words is "one hundred sixty-four billion, four hundred twenty-one million, two hundred fourteen thousand, three hundred three".