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16442134555701 = 35480711518567
BaseRepresentation
bin1110111101000011101110…
…0101101110110000110101
32011012212000121221101011110
43233100323211232300311
54123341442421240301
654545225022025233
73314622264515661
oct357207345566065
964185017841143
1016442134555701
11526a085347128
121a16719718219
139236431a54ca
1440bb36d718a1
151d7a6e89c0d6
hexef43b96ec35

16442134555701 has 4 divisors (see below), whose sum is σ = 21922846074272. Its totient is φ = 10961423037132.

The previous prime is 16442134555633. The next prime is 16442134555709. The reversal of 16442134555701 is 10755543124461.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 16442134555701 - 27 = 16442134555573 is a prime.

It is a super-3 number, since 3×164421345557013 (a number of 41 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16442134555709) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2740355759281 + ... + 2740355759286.

It is an arithmetic number, because the mean of its divisors is an integer number (5480711518568).

Almost surely, 216442134555701 is an apocalyptic number.

It is an amenable number.

16442134555701 is a deficient number, since it is larger than the sum of its proper divisors (5480711518571).

16442134555701 is an equidigital number, since it uses as much as digits as its factorization.

16442134555701 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5480711518570.

The product of its (nonzero) digits is 2016000, while the sum is 48.

The spelling of 16442134555701 in words is "sixteen trillion, four hundred forty-two billion, one hundred thirty-four million, five hundred fifty-five thousand, seven hundred one".

Divisors: 1 3 5480711518567 16442134555701