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16442178042047 is a prime number
BaseRepresentation
bin1110111101000011111000…
…1011100111100010111111
32011012212010122202201012212
43233100332023213202333
54123342040034321142
654545233214051035
73314623333244222
oct357207613474277
964185118681185
1016442178042047
11526a0a794905a
121a167301a9a7b
1392364c1bcb84
1440bb3ca515b9
151d7a735dbd82
hexef43e2e78bf

16442178042047 has 2 divisors, whose sum is σ = 16442178042048. Its totient is φ = 16442178042046.

The previous prime is 16442178042023. The next prime is 16442178042083. The reversal of 16442178042047 is 74024087124461.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 16442178042047 - 26 = 16442178041983 is a prime.

It is a super-3 number, since 3×164421780420473 (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 16442178041986 and 16442178042004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16442178042007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221089021023 + 8221089021024.

It is an arithmetic number, because the mean of its divisors is an integer number (8221089021024).

Almost surely, 216442178042047 is an apocalyptic number.

16442178042047 is a deficient number, since it is larger than the sum of its proper divisors (1).

16442178042047 is an equidigital number, since it uses as much as digits as its factorization.

16442178042047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2408448, while the sum is 50.

The spelling of 16442178042047 in words is "sixteen trillion, four hundred forty-two billion, one hundred seventy-eight million, forty-two thousand, forty-seven".