16442341625531 has 2 divisors, whose sum is σ = 16442341625532. Its totient is φ = 16442341625530.

The previous prime is 16442341625513. The next prime is 16442341625533. The reversal of 16442341625531 is 13552614324461.

Together with previous prime (16442341625513) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (13552614324461) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-16442341625531 is a prime.

It is a super-3 number, since 3×16442341625531³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 16442341625533, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (16442341625533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221170812765 + 8221170812766.

It is an arithmetic number, because the mean of its divisors is an integer number (8221170812766).

Almost surely, 2^{16442341625531} is an apocalyptic number.

16442341625531 is a deficient number, since it is larger than the sum of its proper divisors (1).

16442341625531 is an equidigital number, since it uses as much as digits as its factorization.

16442341625531 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2073600, while the sum is 47.

Adding to 16442341625531 its reverse (13552614324461), we get a palindrome (29994955949992).

The spelling of 16442341625531 in words is "sixteen trillion, four hundred forty-two billion, three hundred forty-one million, six hundred twenty-five thousand, five hundred thirty-one".