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16442344036549 is a prime number
BaseRepresentation
bin1110111101000100100000…
…0100110101100011000101
32011012212120020010002212101
43233101020010311203011
54123342410033132144
654545301503552101
73314630420211214
oct357211004654305
964185506102771
1016442344036549
11526a1826151a2
121a167778bb631
139236776cbc82
1440bb56b0107b
151d7a82e7a6d4
hexef4481358c5

16442344036549 has 2 divisors, whose sum is σ = 16442344036550. Its totient is φ = 16442344036548.

The previous prime is 16442344036543. The next prime is 16442344036631. The reversal of 16442344036549 is 94563044324461.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13479229359649 + 2963114676900 = 3671407^2 + 1721370^2 .

It is a cyclic number.

It is not a de Polignac number, because 16442344036549 - 27 = 16442344036421 is a prime.

It is a super-3 number, since 3×164423440365493 (a number of 41 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 16442344036549.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16442344036543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221172018274 + 8221172018275.

It is an arithmetic number, because the mean of its divisors is an integer number (8221172018275).

Almost surely, 216442344036549 is an apocalyptic number.

It is an amenable number.

16442344036549 is a deficient number, since it is larger than the sum of its proper divisors (1).

16442344036549 is an equidigital number, since it uses as much as digits as its factorization.

16442344036549 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 29859840, while the sum is 55.

The spelling of 16442344036549 in words is "sixteen trillion, four hundred forty-two billion, three hundred forty-four million, thirty-six thousand, five hundred forty-nine".