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164427066353 = 1114947915123
BaseRepresentation
bin1001100100100010011…
…1011110101111110001
3120201102012112102100102
42121020213132233301
510143221312110403
6203311534402145
714610441001124
oct2311047365761
9521365472312
10164427066353
1163807879690
1227a4a360355
13126754b8504
147d5b8763bb
154425470b88
hex26489debf1

164427066353 has 4 divisors (see below), whose sum is σ = 179374981488. Its totient is φ = 149479151220.

The previous prime is 164427066343. The next prime is 164427066359. The reversal of 164427066353 is 353660724461.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 164427066353 - 216 = 164427000817 is a prime.

It is a super-3 number, since 3×1644270663533 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 164427066298 and 164427066307.

It is not an unprimeable number, because it can be changed into a prime (164427066359) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7473957551 + ... + 7473957572.

It is an arithmetic number, because the mean of its divisors is an integer number (44843745372).

Almost surely, 2164427066353 is an apocalyptic number.

It is an amenable number.

164427066353 is a deficient number, since it is larger than the sum of its proper divisors (14947915135).

164427066353 is a wasteful number, since it uses less digits than its factorization.

164427066353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14947915134.

The product of its (nonzero) digits is 2177280, while the sum is 47.

The spelling of 164427066353 in words is "one hundred sixty-four billion, four hundred twenty-seven million, sixty-six thousand, three hundred fifty-three".

Divisors: 1 11 14947915123 164427066353