Base | Representation |
---|---|
bin | 1110111101101100010100… |
… | …1111110111010000000111 |
3 | 2011020220011020012012201011 |
4 | 3233123011033313100013 |
5 | 4124031303201414303 |
6 | 54554230335143051 |
7 | 3315456343421320 |
oct | 357330517672007 |
9 | 64226136165634 |
10 | 16453034013703 |
11 | 5273768853261 |
12 | 1a1885b974a87 |
13 | 92468c329741 |
14 | 40c48c74d447 |
15 | 1d7eab6cb16d |
hex | ef6c53f7407 |
16453034013703 has 4 divisors (see below), whose sum is σ = 18803467444240. Its totient is φ = 14102600583168.
The previous prime is 16453034013679. The next prime is 16453034013737. The reversal of 16453034013703 is 30731043035461.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 16453034013703 - 213 = 16453034005511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16453034013203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1175216715258 + ... + 1175216715271.
It is an arithmetic number, because the mean of its divisors is an integer number (4700866861060).
Almost surely, 216453034013703 is an apocalyptic number.
16453034013703 is a deficient number, since it is larger than the sum of its proper divisors (2350433430537).
16453034013703 is an equidigital number, since it uses as much as digits as its factorization.
16453034013703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2350433430536.
The product of its (nonzero) digits is 272160, while the sum is 40.
The spelling of 16453034013703 in words is "sixteen trillion, four hundred fifty-three billion, thirty-four million, thirteen thousand, seven hundred three".
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