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164540044203 = 354846681401
BaseRepresentation
bin1001100100111101011…
…0011101001110101011
3120201201002010021211020
42121033112131032223
510143434222403303
6203331052103523
714613312204453
oct2311726351653
9521632107736
10164540044203
1163865624607
1227a80164ba3
1312692a24102
147d6c884d63
15443033aa53
hex264f59d3ab

164540044203 has 4 divisors (see below), whose sum is σ = 219386725608. Its totient is φ = 109693362800.

The previous prime is 164540044187. The next prime is 164540044211. The reversal of 164540044203 is 302440045461.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 164540044203 - 24 = 164540044187 is a prime.

It is a super-2 number, since 2×1645400442032 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (164540044223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27423340698 + ... + 27423340703.

It is an arithmetic number, because the mean of its divisors is an integer number (54846681402).

Almost surely, 2164540044203 is an apocalyptic number.

164540044203 is a deficient number, since it is larger than the sum of its proper divisors (54846681405).

164540044203 is an equidigital number, since it uses as much as digits as its factorization.

164540044203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54846681404.

The product of its (nonzero) digits is 46080, while the sum is 33.

Adding to 164540044203 its reverse (302440045461), we get a palindrome (466980089664).

The spelling of 164540044203 in words is "one hundred sixty-four billion, five hundred forty million, forty-four thousand, two hundred three".

Divisors: 1 3 54846681401 164540044203