Base | Representation |
---|---|
bin | 110001001011001… |
… | …1101100101101011 |
3 | 11020222212111122211 |
4 | 1202112131211223 |
5 | 11334403234111 |
6 | 431422225551 |
7 | 55614145345 |
oct | 14226354553 |
9 | 4228774584 |
10 | 1650055531 |
11 | 777460163 |
12 | 3a07252b7 |
13 | 203b10527 |
14 | 119204295 |
15 | 99cda521 |
hex | 6259d96b |
1650055531 has 2 divisors, whose sum is σ = 1650055532. Its totient is φ = 1650055530.
The previous prime is 1650055499. The next prime is 1650055553. The reversal of 1650055531 is 1355500561.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1650055531 - 25 = 1650055499 is a prime.
It is a super-2 number, since 2×16500555312 = 5445366510767383922, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1650055493 and 1650055502.
It is not a weakly prime, because it can be changed into another prime (1650155531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 825027765 + 825027766.
It is an arithmetic number, because the mean of its divisors is an integer number (825027766).
Almost surely, 21650055531 is an apocalyptic number.
1650055531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1650055531 is an equidigital number, since it uses as much as digits as its factorization.
1650055531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11250, while the sum is 31.
The square root of 1650055531 is about 40620.8755567873. The cubic root of 1650055531 is about 1181.6790066987.
The spelling of 1650055531 in words is "one billion, six hundred fifty million, fifty-five thousand, five hundred thirty-one".
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