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165308149604413 is a prime number
BaseRepresentation
bin100101100101100011001101…
…100010010010000000111101
3210200022022020011122222222201
4211211203031202102000331
5133131402042244320123
61343325303205111501
746551056023360234
oct4545431542220075
9720268204588881
10165308149604413
11487438799714a2
12166599b09b8591
13713165111b20a
142cb6d58521b1b
15141a09e9505ad
hex9658cd89203d

165308149604413 has 2 divisors, whose sum is σ = 165308149604414. Its totient is φ = 165308149604412.

The previous prime is 165308149604387. The next prime is 165308149604449. The reversal of 165308149604413 is 314406941803561.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103673999653849 + 61634149950564 = 10182043^2 + 7850742^2 .

It is an emirp because it is prime and its reverse (314406941803561) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 165308149604413 - 213 = 165308149596221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (165308149604483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82654074802206 + 82654074802207.

It is an arithmetic number, because the mean of its divisors is an integer number (82654074802207).

Almost surely, 2165308149604413 is an apocalyptic number.

It is an amenable number.

165308149604413 is a deficient number, since it is larger than the sum of its proper divisors (1).

165308149604413 is an equidigital number, since it uses as much as digits as its factorization.

165308149604413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7464960, while the sum is 55.

The spelling of 165308149604413 in words is "one hundred sixty-five trillion, three hundred eight billion, one hundred forty-nine million, six hundred four thousand, four hundred thirteen".