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165441130433 = 1307821915401
BaseRepresentation
bin1001101000010100001…
…1110100111111000001
3120211000212200012202022
42122011003310333001
510202310412133213
6204000321331225
714644533256145
oct2320503647701
9524025605668
10165441130433
1164188228a77
1228091a96b15
13127a760b027
148016405225
1544844ce308
hex26850f4fc1

165441130433 has 8 divisors (see below), whose sum is σ = 165598607520. Its totient is φ = 165283703200.

The previous prime is 165441130409. The next prime is 165441130453. The reversal of 165441130433 is 334031144561.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 165441130433 - 224 = 165424353217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 165441130393 and 165441130402.

It is not an unprimeable number, because it can be changed into a prime (165441130403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10734533 + ... + 10749933.

It is an arithmetic number, because the mean of its divisors is an integer number (20699825940).

Almost surely, 2165441130433 is an apocalyptic number.

It is an amenable number.

165441130433 is a deficient number, since it is larger than the sum of its proper divisors (157477087).

165441130433 is a wasteful number, since it uses less digits than its factorization.

165441130433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24927.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 165441130433 its reverse (334031144561), we get a palindrome (499472274994).

The spelling of 165441130433 in words is "one hundred sixty-five billion, four hundred forty-one million, one hundred thirty thousand, four hundred thirty-three".

Divisors: 1 1307 8219 15401 10742233 20129107 126580819 165441130433