Base | Representation |
---|---|
bin | 1111000011100110000010… |
… | …0001000100111010100111 |
3 | 2011121120212012220200110211 |
4 | 3300321200201010322213 |
5 | 4132211424322224112 |
6 | 55112555210200251 |
7 | 3326006016561301 |
oct | 360714041047247 |
9 | 64546765820424 |
10 | 16554423242407 |
11 | 5302767390456 |
12 | 1a34436a23087 |
13 | 9310c98b5cab |
14 | 41334a0ba971 |
15 | 1da94287e0a7 |
hex | f0e60844ea7 |
16554423242407 has 2 divisors, whose sum is σ = 16554423242408. Its totient is φ = 16554423242406.
The previous prime is 16554423242389. The next prime is 16554423242471. The reversal of 16554423242407 is 70424232445561.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16554423242407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16554423246407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8277211621203 + 8277211621204.
It is an arithmetic number, because the mean of its divisors is an integer number (8277211621204).
Almost surely, 216554423242407 is an apocalyptic number.
16554423242407 is a deficient number, since it is larger than the sum of its proper divisors (1).
16554423242407 is an equidigital number, since it uses as much as digits as its factorization.
16554423242407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6451200, while the sum is 49.
Adding to 16554423242407 its reverse (70424232445561), we get a palindrome (86978655687968).
The spelling of 16554423242407 in words is "sixteen trillion, five hundred fifty-four billion, four hundred twenty-three million, two hundred forty-two thousand, four hundred seven".
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