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165551312133551 is a prime number
BaseRepresentation
bin100101101001000101101011…
…001001101101110110101111
3210201011112212120212100101102
4211221011223021231312233
5133144343041401233201
61344033120050033315
746604454562642511
oct4551055311556657
9721145776770342
10165551312133551
1148827a0a870683
1216698b5357883b
13714b56376bb56
142cc4a24c03bb1
15142158235726b
hex96916b26ddaf

165551312133551 has 2 divisors, whose sum is σ = 165551312133552. Its totient is φ = 165551312133550.

The previous prime is 165551312133539. The next prime is 165551312133721. The reversal of 165551312133551 is 155331213155561.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-165551312133551 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 165551312133496 and 165551312133505.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (165551312133521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82775656066775 + 82775656066776.

It is an arithmetic number, because the mean of its divisors is an integer number (82775656066776).

Almost surely, 2165551312133551 is an apocalyptic number.

165551312133551 is a deficient number, since it is larger than the sum of its proper divisors (1).

165551312133551 is an equidigital number, since it uses as much as digits as its factorization.

165551312133551 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1012500, while the sum is 47.

The spelling of 165551312133551 in words is "one hundred sixty-five trillion, five hundred fifty-one billion, three hundred twelve million, one hundred thirty-three thousand, five hundred fifty-one".