Base | Representation |
---|---|
bin | 100101101001000101101011… |
… | …001001101101110110101111 |
3 | 210201011112212120212100101102 |
4 | 211221011223021231312233 |
5 | 133144343041401233201 |
6 | 1344033120050033315 |
7 | 46604454562642511 |
oct | 4551055311556657 |
9 | 721145776770342 |
10 | 165551312133551 |
11 | 48827a0a870683 |
12 | 16698b5357883b |
13 | 714b56376bb56 |
14 | 2cc4a24c03bb1 |
15 | 142158235726b |
hex | 96916b26ddaf |
165551312133551 has 2 divisors, whose sum is σ = 165551312133552. Its totient is φ = 165551312133550.
The previous prime is 165551312133539. The next prime is 165551312133721. The reversal of 165551312133551 is 155331213155561.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-165551312133551 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 165551312133496 and 165551312133505.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (165551312133521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82775656066775 + 82775656066776.
It is an arithmetic number, because the mean of its divisors is an integer number (82775656066776).
Almost surely, 2165551312133551 is an apocalyptic number.
165551312133551 is a deficient number, since it is larger than the sum of its proper divisors (1).
165551312133551 is an equidigital number, since it uses as much as digits as its factorization.
165551312133551 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1012500, while the sum is 47.
The spelling of 165551312133551 in words is "one hundred sixty-five trillion, five hundred fifty-one billion, three hundred twelve million, one hundred thirty-three thousand, five hundred fifty-one".
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