Base | Representation |
---|---|
bin | 1111000100001100010110… |
… | …1111000101111011111101 |
3 | 2011122120102012210200221021 |
4 | 3301003011233011323331 |
5 | 4132344012101200023 |
6 | 55121420124104141 |
7 | 3326521663212151 |
oct | 361030557057375 |
9 | 64576365720837 |
10 | 16564711350013 |
11 | 5307066796a22 |
12 | 1a36428395051 |
13 | 932079199228 |
14 | 413a445d9061 |
15 | 1dad45b9c35d |
hex | f10c5bc5efd |
16564711350013 has 2 divisors, whose sum is σ = 16564711350014. Its totient is φ = 16564711350012.
The previous prime is 16564711350001. The next prime is 16564711350091. The reversal of 16564711350013 is 31005311746561.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13433375834649 + 3131335515364 = 3665157^2 + 1769558^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16564711350013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16564711359013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8282355675006 + 8282355675007.
It is an arithmetic number, because the mean of its divisors is an integer number (8282355675007).
Almost surely, 216564711350013 is an apocalyptic number.
It is an amenable number.
16564711350013 is a deficient number, since it is larger than the sum of its proper divisors (1).
16564711350013 is an equidigital number, since it uses as much as digits as its factorization.
16564711350013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 43.
The spelling of 16564711350013 in words is "sixteen trillion, five hundred sixty-four billion, seven hundred eleven million, three hundred fifty thousand, thirteen".
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