Base | Representation |
---|---|
bin | 11000001011011100111… |
… | …100001001101111110011 |
3 | 12212211210021001102220212 |
4 | 120023130330021233303 |
5 | 204210340404213324 |
6 | 3311151221454335 |
7 | 231021052044236 |
oct | 30133474115763 |
9 | 5784707042825 |
10 | 1661564132339 |
11 | 5907356aa301 |
12 | 22a0325713ab |
13 | c08b973b307 |
14 | 5a5c4bb941d |
15 | 2d34b2ed70e |
hex | 182dcf09bf3 |
1661564132339 has 2 divisors, whose sum is σ = 1661564132340. Its totient is φ = 1661564132338.
The previous prime is 1661564132311. The next prime is 1661564132363. The reversal of 1661564132339 is 9332314651661.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1661564132339 is a prime.
It is a super-2 number, since 2×16615641323392 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1661564132369) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 830782066169 + 830782066170.
It is an arithmetic number, because the mean of its divisors is an integer number (830782066170).
Almost surely, 21661564132339 is an apocalyptic number.
1661564132339 is a deficient number, since it is larger than the sum of its proper divisors (1).
1661564132339 is an equidigital number, since it uses as much as digits as its factorization.
1661564132339 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2099520, while the sum is 50.
The spelling of 1661564132339 in words is "one trillion, six hundred sixty-one billion, five hundred sixty-four million, one hundred thirty-two thousand, three hundred thirty-nine".
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