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16622260113 = 35540753371
BaseRepresentation
bin11110111101100001…
…11000111110010001
31120220102201022012110
433132300320332101
5233020244310423
611345224415533
71125625610514
oct173660707621
946812638173
1016622260113
11705a918058
12327a9175a9
13174b976b94
14b39870d7b
1567445e193
hex3dec38f91

16622260113 has 4 divisors (see below), whose sum is σ = 22163013488. Its totient is φ = 11081506740.

The previous prime is 16622260099. The next prime is 16622260129. The reversal of 16622260113 is 31106222661.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-16622260113 is a prime.

It is a super-3 number, since 3×166222601133 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16622260163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2770376683 + ... + 2770376688.

It is an arithmetic number, because the mean of its divisors is an integer number (5540753372).

Almost surely, 216622260113 is an apocalyptic number.

It is an amenable number.

16622260113 is a deficient number, since it is larger than the sum of its proper divisors (5540753375).

16622260113 is an equidigital number, since it uses as much as digits as its factorization.

16622260113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5540753374.

The product of its (nonzero) digits is 5184, while the sum is 30.

Adding to 16622260113 its reverse (31106222661), we get a palindrome (47728482774).

The spelling of 16622260113 in words is "sixteen billion, six hundred twenty-two million, two hundred sixty thousand, one hundred thirteen".

Divisors: 1 3 5540753371 16622260113