Base | Representation |
---|---|
bin | 1111001001011001001001… |
… | …1101101001001101101010 |
3 | 2011222010000001200020111102 |
4 | 3302112102131221031222 |
5 | 4140324441113413424 |
6 | 55230432440001402 |
7 | 3336133525433411 |
oct | 362262235511552 |
9 | 64863001606442 |
10 | 16654045451114 |
11 | 5340a3953a345 |
12 | 1a4b7ba160262 |
13 | 93a61505b996 |
14 | 4180bacb8478 |
15 | 1dd3238407ae |
hex | f259276936a |
16654045451114 has 4 divisors (see below), whose sum is σ = 24981068176674. Its totient is φ = 8327022725556.
The previous prime is 16654045451101. The next prime is 16654045451117. The reversal of 16654045451114 is 41115454045661.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10019016470089 + 6635028981025 = 3165283^2 + 2575855^2 .
It is not an unprimeable number, because it can be changed into a prime (16654045451117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4163511362777 + ... + 4163511362780.
Almost surely, 216654045451114 is an apocalyptic number.
16654045451114 is a deficient number, since it is larger than the sum of its proper divisors (8327022725560).
16654045451114 is an equidigital number, since it uses as much as digits as its factorization.
16654045451114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8327022725559.
The product of its (nonzero) digits is 1152000, while the sum is 47.
Adding to 16654045451114 its reverse (41115454045661), we get a palindrome (57769499496775).
The spelling of 16654045451114 in words is "sixteen trillion, six hundred fifty-four billion, forty-five million, four hundred fifty-one thousand, one hundred fourteen".
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