Base | Representation |
---|---|
bin | 1111001010011001010011… |
… | …0100000001001111110101 |
3 | 2012000202110002210202200021 |
4 | 3302212110310001033311 |
5 | 4141120222233142331 |
6 | 55242401233045141 |
7 | 3340313324121001 |
oct | 362462464011765 |
9 | 65022402722607 |
10 | 16671264740341 |
11 | 5348275366192 |
12 | 1a530049b67b1 |
13 | 93c12a601113 |
14 | 418c71b5b701 |
15 | 1dd9d03d2211 |
hex | f2994d013f5 |
16671264740341 has 2 divisors, whose sum is σ = 16671264740342. Its totient is φ = 16671264740340.
The previous prime is 16671264740303. The next prime is 16671264740477. The reversal of 16671264740341 is 14304746217661.
16671264740341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14977287002500 + 1693977737841 = 3870050^2 + 1301529^2 .
It is a cyclic number.
It is not a de Polignac number, because 16671264740341 - 213 = 16671264732149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16671268740341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8335632370170 + 8335632370171.
It is an arithmetic number, because the mean of its divisors is an integer number (8335632370171).
Almost surely, 216671264740341 is an apocalyptic number.
It is an amenable number.
16671264740341 is a deficient number, since it is larger than the sum of its proper divisors (1).
16671264740341 is an equidigital number, since it uses as much as digits as its factorization.
16671264740341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4064256, while the sum is 52.
The spelling of 16671264740341 in words is "sixteen trillion, six hundred seventy-one billion, two hundred sixty-four million, seven hundred forty thousand, three hundred forty-one".
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