Search a number
-
+
167074949113 is a prime number
BaseRepresentation
bin1001101110011001110…
…0010110011111111001
3120222020201222210122021
42123212130112133321
510214132141332423
6204430403554441
715033162431002
oct2334634263771
9528221883567
10167074949113
11649464a9146
122846908ba21
13129a7c54c47
14812d3c01a9
15452cb5d95d
hex26e67167f9

167074949113 has 2 divisors, whose sum is σ = 167074949114. Its totient is φ = 167074949112.

The previous prime is 167074949101. The next prime is 167074949299. The reversal of 167074949113 is 311949470761.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 167074927504 + 21609 = 408748^2 + 147^2 .

It is a cyclic number.

It is not a de Polignac number, because 167074949113 - 25 = 167074949081 is a prime.

It is a super-2 number, since 2×1670749491132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (167074749113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83537474556 + 83537474557.

It is an arithmetic number, because the mean of its divisors is an integer number (83537474557).

Almost surely, 2167074949113 is an apocalyptic number.

It is an amenable number.

167074949113 is a deficient number, since it is larger than the sum of its proper divisors (1).

167074949113 is an equidigital number, since it uses as much as digits as its factorization.

167074949113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1143072, while the sum is 52.

The spelling of 167074949113 in words is "one hundred sixty-seven billion, seventy-four million, nine hundred forty-nine thousand, one hundred thirteen".