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16725444133 is a prime number
BaseRepresentation
bin11111001001110101…
…00000011000100101
31121011121212121001211
433210322200120211
5233223203203013
611403352151421
71131320633536
oct174472403045
947147777054
1016725444133
117103093802
1232a9398571
131767163a08
14b4945068d
1567d54223d
hex3e4ea0625

16725444133 has 2 divisors, whose sum is σ = 16725444134. Its totient is φ = 16725444132.

The previous prime is 16725444121. The next prime is 16725444143. The reversal of 16725444133 is 33144452761.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12625219044 + 4100225089 = 112362^2 + 64033^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16725444133 is a prime.

It is a super-2 number, since 2×167254441332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16725444143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8362722066 + 8362722067.

It is an arithmetic number, because the mean of its divisors is an integer number (8362722067).

Almost surely, 216725444133 is an apocalyptic number.

It is an amenable number.

16725444133 is a deficient number, since it is larger than the sum of its proper divisors (1).

16725444133 is an equidigital number, since it uses as much as digits as its factorization.

16725444133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 241920, while the sum is 40.

Adding to 16725444133 its reverse (33144452761), we get a palindrome (49869896894).

The spelling of 16725444133 in words is "sixteen billion, seven hundred twenty-five million, four hundred forty-four thousand, one hundred thirty-three".