Base | Representation |
---|---|
bin | 11111001011101011… |
… | …00011110101111001 |
3 | 1121012201000002112121 |
4 | 33211311203311321 |
5 | 233241134043133 |
6 | 11405104041241 |
7 | 1131566340625 |
oct | 174565436571 |
9 | 47181002477 |
10 | 16740924793 |
11 | 71108a763a |
12 | 32b2603221 |
13 | 176a424078 |
14 | b4b520185 |
15 | 67ea9e02d |
hex | 3e5d63d79 |
16740924793 has 2 divisors, whose sum is σ = 16740924794. Its totient is φ = 16740924792.
The previous prime is 16740924791. The next prime is 16740924803. The reversal of 16740924793 is 39742904761.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10276282384 + 6464642409 = 101372^2 + 80403^2 .
It is a cyclic number.
It is not a de Polignac number, because 16740924793 - 21 = 16740924791 is a prime.
Together with 16740924791, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 16740924793.
It is not a weakly prime, because it can be changed into another prime (16740924791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8370462396 + 8370462397.
It is an arithmetic number, because the mean of its divisors is an integer number (8370462397).
Almost surely, 216740924793 is an apocalyptic number.
It is an amenable number.
16740924793 is a deficient number, since it is larger than the sum of its proper divisors (1).
16740924793 is an equidigital number, since it uses as much as digits as its factorization.
16740924793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2286144, while the sum is 52.
The spelling of 16740924793 in words is "sixteen billion, seven hundred forty million, nine hundred twenty-four thousand, seven hundred ninety-three".
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