Base | Representation |
---|---|
bin | 1111010011101010001010… |
… | …1001101100010011110101 |
3 | 2012120222020021000101012221 |
4 | 3310322202221230103311 |
5 | 4201222140120012432 |
6 | 55443441155242341 |
7 | 3354646160362453 |
oct | 364724251542365 |
9 | 65528207011187 |
10 | 16830410704117 |
11 | 53a981209028a |
12 | 1a79a1a5a93b1 |
13 | 95114094855a |
14 | 42284c07b9d3 |
15 | 1e2be6dc1b97 |
hex | f4ea2a6c4f5 |
16830410704117 has 4 divisors (see below), whose sum is σ = 16830497311936. Its totient is φ = 16830324096300.
The previous prime is 16830410704099. The next prime is 16830410704123. The reversal of 16830410704117 is 71140701403861.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 16830410704117 - 239 = 16280654890229 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16830410704147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43011759 + ... + 43401292.
It is an arithmetic number, because the mean of its divisors is an integer number (4207624327984).
Almost surely, 216830410704117 is an apocalyptic number.
It is an amenable number.
16830410704117 is a deficient number, since it is larger than the sum of its proper divisors (86607819).
16830410704117 is an equidigital number, since it uses as much as digits as its factorization.
16830410704117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86607818.
The product of its (nonzero) digits is 112896, while the sum is 43.
The spelling of 16830410704117 in words is "sixteen trillion, eight hundred thirty billion, four hundred ten million, seven hundred four thousand, one hundred seventeen".
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