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168401323 is a prime number
BaseRepresentation
bin10100000100110…
…01100110101011
3102201212200012001
422002121212223
5321102320243
624413231431
74113246646
oct1202314653
9381780161
10168401323
1187070452
1248492577
1328b7276c
1418518a5d
15ebb6a4d
hexa0999ab

168401323 has 2 divisors, whose sum is σ = 168401324. Its totient is φ = 168401322.

The previous prime is 168401257. The next prime is 168401341. The reversal of 168401323 is 323104861.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-168401323 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 168401291 and 168401300.

It is not a weakly prime, because it can be changed into another prime (168401353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84200661 + 84200662.

It is an arithmetic number, because the mean of its divisors is an integer number (84200662).

Almost surely, 2168401323 is an apocalyptic number.

168401323 is a deficient number, since it is larger than the sum of its proper divisors (1).

168401323 is an equidigital number, since it uses as much as digits as its factorization.

168401323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

The square root of 168401323 is about 12976.9535330909. The cubic root of 168401323 is about 552.2238587854.

The spelling of 168401323 in words is "one hundred sixty-eight million, four hundred one thousand, three hundred twenty-three".