Base | Representation |
---|---|
bin | 1111010100010001100011… |
… | …0010010000101001110101 |
3 | 2012121222112000220010211001 |
4 | 3311010120302100221311 |
5 | 4201410313021034323 |
6 | 55452350211443301 |
7 | 3355502151105346 |
oct | 365043062205165 |
9 | 65558460803731 |
10 | 16840982596213 |
11 | 54032476a5296 |
12 | 1a7ba8abb6531 |
13 | 952136c6c8c9 |
14 | 42317214c0cd |
15 | 1e31150993ad |
hex | f5118c90a75 |
16840982596213 has 2 divisors, whose sum is σ = 16840982596214. Its totient is φ = 16840982596212.
The previous prime is 16840982596091. The next prime is 16840982596247. The reversal of 16840982596213 is 31269528904861.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10517457621969 + 6323524974244 = 3243063^2 + 2514662^2 .
It is a cyclic number.
It is not a de Polignac number, because 16840982596213 - 241 = 14641959340661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16840982596013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8420491298106 + 8420491298107.
It is an arithmetic number, because the mean of its divisors is an integer number (8420491298107).
Almost surely, 216840982596213 is an apocalyptic number.
It is an amenable number.
16840982596213 is a deficient number, since it is larger than the sum of its proper divisors (1).
16840982596213 is an equidigital number, since it uses as much as digits as its factorization.
16840982596213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 44789760, while the sum is 64.
The spelling of 16840982596213 in words is "sixteen trillion, eight hundred forty billion, nine hundred eighty-two million, five hundred ninety-six thousand, two hundred thirteen".
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