Base | Representation |
---|---|
bin | 1111010100101100000110… |
… | …1101010001101010011011 |
3 | 2012122122220212101101100101 |
4 | 3311023001231101222123 |
5 | 4202014413032401202 |
6 | 55455525435120231 |
7 | 3356143624513603 |
oct | 365130155215233 |
9 | 65578825341311 |
10 | 16848111606427 |
11 | 5406275855172 |
12 | 1a8133a5a3077 |
13 | 952a01c0594a |
14 | 42364ac8bc03 |
15 | 1e33d0d98887 |
hex | f52c1b51a9b |
16848111606427 has 2 divisors, whose sum is σ = 16848111606428. Its totient is φ = 16848111606426.
The previous prime is 16848111606401. The next prime is 16848111606439. The reversal of 16848111606427 is 72460611184861.
It is a strong prime.
It is an emirp because it is prime and its reverse (72460611184861) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16848111606427 is a prime.
It is not a weakly prime, because it can be changed into another prime (16848111606467) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8424055803213 + 8424055803214.
It is an arithmetic number, because the mean of its divisors is an integer number (8424055803214).
Almost surely, 216848111606427 is an apocalyptic number.
16848111606427 is a deficient number, since it is larger than the sum of its proper divisors (1).
16848111606427 is an equidigital number, since it uses as much as digits as its factorization.
16848111606427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3096576, while the sum is 55.
The spelling of 16848111606427 in words is "sixteen trillion, eight hundred forty-eight billion, one hundred eleven million, six hundred six thousand, four hundred twenty-seven".
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