Base | Representation |
---|---|
bin | 1001110101010000011… |
… | …1011001100010000001 |
3 | 121010222222021112201101 |
4 | 2131110013121202001 |
5 | 10231414211402043 |
6 | 205333133334401 |
7 | 15126604246606 |
oct | 2352407314201 |
9 | 533888245641 |
10 | 168914950273 |
11 | 657000a4263 |
12 | 288a1337401 |
13 | 12c0c20c224 |
14 | 826590a6ad |
15 | 45d946924d |
hex | 27541d9881 |
168914950273 has 2 divisors, whose sum is σ = 168914950274. Its totient is φ = 168914950272.
The previous prime is 168914950223. The next prime is 168914950277. The reversal of 168914950273 is 372059419861.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 156462175809 + 12452774464 = 395553^2 + 111592^2 .
It is a cyclic number.
It is not a de Polignac number, because 168914950273 - 221 = 168912853121 is a prime.
It is a super-3 number, since 3×1689149502733 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (168914950277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84457475136 + 84457475137.
It is an arithmetic number, because the mean of its divisors is an integer number (84457475137).
It is a 1-persistent number, because it is pandigital, but 2⋅168914950273 = 337829900546 is not.
Almost surely, 2168914950273 is an apocalyptic number.
It is an amenable number.
168914950273 is a deficient number, since it is larger than the sum of its proper divisors (1).
168914950273 is an equidigital number, since it uses as much as digits as its factorization.
168914950273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3265920, while the sum is 55.
The spelling of 168914950273 in words is "one hundred sixty-eight billion, nine hundred fourteen million, nine hundred fifty thousand, two hundred seventy-three".
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