Base | Representation |
---|---|
bin | 11000100110010000010… |
… | …101111011001100001001 |
3 | 12222121001222002202002122 |
4 | 120212100111323030021 |
5 | 210143311004021042 |
6 | 3332311102141025 |
7 | 233060203231334 |
oct | 30462025731411 |
9 | 5877058082078 |
10 | 1690343813897 |
11 | 5a1964019aa2 |
12 | 233724881775 |
13 | c352504689b |
14 | 5bb5512561b |
15 | 2de82c267d2 |
hex | 1899057b309 |
1690343813897 has 2 divisors, whose sum is σ = 1690343813898. Its totient is φ = 1690343813896.
The previous prime is 1690343813819. The next prime is 1690343813959. The reversal of 1690343813897 is 7983183430961.
It is an a-pointer prime, because the next prime (1690343813959) can be obtained adding 1690343813897 to its sum of digits (62).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1423735785616 + 266608028281 = 1193204^2 + 516341^2 .
It is a cyclic number.
It is not a de Polignac number, because 1690343813897 - 234 = 1673163944713 is a prime.
It is not a weakly prime, because it can be changed into another prime (1690343816897) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 845171906948 + 845171906949.
It is an arithmetic number, because the mean of its divisors is an integer number (845171906949).
Almost surely, 21690343813897 is an apocalyptic number.
It is an amenable number.
1690343813897 is a deficient number, since it is larger than the sum of its proper divisors (1).
1690343813897 is an equidigital number, since it uses as much as digits as its factorization.
1690343813897 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23514624, while the sum is 62.
The spelling of 1690343813897 in words is "one trillion, six hundred ninety billion, three hundred forty-three million, eight hundred thirteen thousand, eight hundred ninety-seven".
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