1691312652650 has 12 divisors (see below), whose sum is σ = 3145841534022. Its totient is φ = 676525061040.

The previous prime is 1691312652647. The next prime is 1691312652691. The reversal of 1691312652650 is 562562131961.

It can be written as a sum of positive squares in 3 ways, for example, as 1320722697529 + 370589955121 = 1149227^2 + 608761^2 .

It is a hoax number, since the sum of its digits (47) coincides with the sum of the digits of its distinct prime factors.

It is a junction number, because it is equal to n+sod(n) for n = 1691312652595 and 1691312652604.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 16913126477 + ... + 16913126576.

Almost surely, 2^{1691312652650} is an apocalyptic number.

1691312652650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1691312652650 is a deficient number, since it is larger than the sum of its proper divisors (1454528881372).

1691312652650 is a wasteful number, since it uses less digits than its factorization.

1691312652650 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33826253065 (or 33826253060 counting only the distinct ones).

The product of its (nonzero) digits is 583200, while the sum is 47.

The spelling of 1691312652650 in words is "one trillion, six hundred ninety-one billion, three hundred twelve million, six hundred fifty-two thousand, six hundred fifty".