16913580253 has 4 divisors (see below), whose sum is σ = 17459179648. Its totient is φ = 16367980860.

The previous prime is 16913580221. The next prime is 16913580289. The reversal of 16913580253 is 35208531961.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16913580253 - 2⁵ = 16913580221 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16913580353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272799651 + ... + 272799712.

It is an arithmetic number, because the mean of its divisors is an integer number (4364794912).

Almost surely, 2^16913580253 is an apocalyptic number.

It is an amenable number.

16913580253 is a deficient number, since it is larger than the sum of its proper divisors (545599395).

16913580253 is an equidigital number, since it uses as much as digits as its factorization.

16913580253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 545599394.

The product of its (nonzero) digits is 194400, while the sum is 43.

The spelling of 16913580253 in words is "sixteen billion, nine hundred thirteen million, five hundred eighty thousand, two hundred fifty-three".