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16933088428343 = 33151157366853
BaseRepresentation
bin1111011001101000101010…
…1110001000000100110111
32012221210021001021012112222
43312122022232020010313
54204412431114201333
6100002541535232555
73365242500546233
oct366321256100467
965853231235488
1016933088428343
115439311a7820a
121a958b507875b
1395aa251424a9
144277cc9b35c3
151e5706241298
hexf668ab88137

16933088428343 has 4 divisors (see below), whose sum is σ = 16984245795528. Its totient is φ = 16881931061160.

The previous prime is 16933088428313. The next prime is 16933088428387. The reversal of 16933088428343 is 34382488033961.

16933088428343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 16933088428343 - 212 = 16933088424247 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16933088428313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25578683096 + ... + 25578683757.

It is an arithmetic number, because the mean of its divisors is an integer number (4246061448882).

Almost surely, 216933088428343 is an apocalyptic number.

16933088428343 is a deficient number, since it is larger than the sum of its proper divisors (51157367185).

16933088428343 is an equidigital number, since it uses as much as digits as its factorization.

16933088428343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51157367184.

The product of its (nonzero) digits is 71663616, while the sum is 62.

The spelling of 16933088428343 in words is "sixteen trillion, nine hundred thirty-three billion, eighty-eight million, four hundred twenty-eight thousand, three hundred forty-three".

Divisors: 1 331 51157366853 16933088428343